New Crossword and Solution for 19.3
Vector 19:4, page 43
Transcribed from the printed issue; not yet reviewed. Read it in the PDF of the issue, page 43
Solution to Crossword in 19:3¶

New Crossword¶

Across¶
- Smallest positive number in vector
V - Cumulative product of vector
V - Branch to line labelled
JV - The larger of
MorC (T+¯1),(T+¯2),...,(T+¯5)for scalarT- Convert indices in
SO1to origin 0 - The remainder of
V2÷GF - All but first
Pelements of vectorR M=Mfor any arrayMV[1;Y⍴1]~(LB÷2)≠K+K,×/⍴10 20 30 40 ... 1230('MAT←12 11⍴¯1'~'A1 ⍴←')[2 3 1 4]¯1↓1↓'APL2'!4V1[(1+⍴V1)-⍳⍴V1](⍳4),5+⍳4_____⍴Ais first element ofA, as a scalar,(T-⌊T),[1.5]T-⌊Tfor vectorT__AreturnsA, but promotes scalarAto a vector- Distinct elements of character array
CV
Down¶
- Distinct elements of vector
V, whose length isL M[;1]>M[;2]for two-columnM- Bring objects into active workspace without overwriting existing objects
(V×-R1)+(V×J)- Distinct elements of sorted,non-negative, numeric vector
V - Branch to line labelled
L0if bitTFis 1 . J-(MB×MB×P92A×P92A)*0.5- The next larger integer at or above
S K1[S2⍴⍳⍴K1]- Number of columns in matrix
MT G1+G1- Number of dimensions in matrix
MV01A (⍕1↓1↓⌽⍳5)~' '__X is (2+⍳X-2),⍳2∧/~C-5×⌊C÷5- Non-interactive full-screen interface