Solution and New Crossword
Vector 18:3, page 49
Transcribed from the printed issue; not yet reviewed. Read it in the PDF of the issue, page 49
Solution to Crossword in 18.2¶

New Crossword¶

Across¶
+⌿MATV[((⍴V)+(⎕IO=1)-⎕IO=0)-⍳⍴V],1+⍳10⍟Nfor integer scalar N>0- Are any of the corresponding rows in matrices M and W identical?
(M×M≥N)+(N×M<N)- Pythagoras:
(______+B*2)=C*2 ⊃,/Awhere A is a vector of simple vectors-V-1000.5×VR(⍳0)⍴⍒V⍳0, using shape- Add up
A∊Vfor vector V, using dyadic⍳(⍴N)+(⍴K)for vectors N and KN-1|N⌽⍴⍉M- N random numbers from the set
(ML-1),(ML-2),(ML-3) ...,(ML-59) - The value of X, if
TP←⍟X ⌽¯2↑1⌽'NUMBER'V[⍳15]R[I]××/N[I;]for all I⍳0, using reshapeMATRIX, with values formatted to one decimal place
Down¶
- Are any of the values of matrix M in vector V?
- Is either M or N true?
- Replicate each element A times
- Are both T and B0 true?
- Reverse the values in each row of M
(V≥0)∧(V≤9)'1'or'2'at random (origin 1)⎕__tells you how much room there is-⌊-AR(2×V[1])*(2×V[2])for 2-element vector V in origin 1- What gave birth to this erroneous situation?
×/(⌽⍳2)/1+⍳2in origin 12⍴2⌽⍎'''V←0'''+\(⍴V)⍴¯1for vector V in origin 1I,-I×*¯10- Bit vector to index vector converter
M≠M, but faster)VARSor)FNSunder program control- OK random numbers from
⍳T5 ____your boat⊃Nin Sharp APL- Stick vector NX on the right side of matrix AMT as a new column
1,(NP-1)⍴0+/+\(+/+\(+/+\⍳2)⍴1)⍴1in origin 1RRR[_____]is in ascending order(N⍴T[1]),(N⍴T[2]),(N⍴T[3]), ...for scalar N- Format to V decimal places
(A>0)-(A<0)1⍴Ifor scalar I