Crossword
Vector 17:2, page 32
Transcribed from the printed issue; not yet reviewed. Read it in the PDF of the issue, page 32

Across¶
- The first element of A, as a scalar
- The values of x such that
(∧/(⍳⍴F)∊x)∧((⍴x)=⍴F)∧(1↓F[x])∧.≥¯1↓F[x] - Resume the function that called the currently suspended function
- The rank of the shape of F (or is it the shape of the rank?)
(N>L)-N<L⍉B÷|B+B=0- Clear the state indicator
(~X∊DG)/X1⍲B- Subtract from the absolute value of M ...
- Is (non-nested) A numeric?
(12↓V),12↑V- The opposite of
'⌈/' - M, all strung out
∨/,Z1=20- Add the magnitude of K to VM
- The product of A and ...
- The result of 9 across
((⍴B)=+/B)⍴⎕IOfor bit vector B- e to the power NVP, times five
NX-1|NX- Inverse of
+\Vfor vectorV - The sin of one radian
(NE+1)-⍳NEin origin 1- Assuming
V[]←0and∧/I∊⍳⍴V, doV←(⍳⍴V)∊I - Go to the line labelled L1
Down¶
T×0+\RR=RRfor vector RR in origin 1⍳0if AE is numeric;' 'if AE is character⎕NL 3- Multiply alternate elements of A, whose shape is PTB, by the two values in M
⍒Swithout using⍒10-FLEX×⌊10÷FLEX- Branch to the line labelled P if D is positive, to Z if zero, to N if negative
- IS the answer obvious?
((SE≠0)>SE∊K)/SE-V11-BG- M2 is not an element of ...
0=(M[;1]∧N[;1])-(M[;2]∧N[;2])for two-column matrices M and N- The sum of all but the first X elements of I, but no less than zero
e+e''⍴⍋V(B×B)*.5-A- Pi less than 5
⌽(-N)↓L((V0/⍳⍴V0),⎕IO+⍴V0)[⎕IO]- V1 gets ...
- MAT, less one dimension
Solution to Crossword in 17.1¶
